1.0 Fun with
Numbers:
Before we study numbers and their properties, let us familiarise few interesting things
about numbers
Telling a number:
Can you tell a number a friend has in his mind without him
revealing that number to you?
Here are the steps
Step No |
Action |
Example |
1 |
Ask your
friend to keep a number in his mind |
Say 27 |
2 |
Ask him to
multiply that number by 2 |
54 |
3 |
Ask him to
add 4 to that |
58 |
4 |
Ask him to
divide the number by 2 |
29 |
5 |
Ask him to
reveal the number to you |
29 |
Now you subtract 2
from that number and tell him that his number is 27!
What is the mathematics behind that?
Let x be the number.
Step No |
Action |
Example |
1 |
Ask your
friend to keep a number in his mind |
Say x |
2 |
Ask him to
multiply that number by 2 |
2x |
3 |
Ask him to
add 4 to that |
2x+4 |
4 |
Ask him to
divide the number by 2 |
x+2 |
5 |
Ask him to
reveal the number to you |
x+2 |
When you subtract 2
from that you get x which is the number he had in his mind
Can you construct a different method by using different
multiplication factor in stead of 2
and also different additional factor instead of 4?
There are innumerable numbers of ways, we can formulate
above type of tricks/puzzles.
Let us now look at some interesting facts about some
numbers.
Speciality of numbers from 1 to 9:
1.
Consider the number 123456789. Sum of individual digits of
this number is 45(=1+2+3+4+5+6+7+8+9)
2.
Now multiply 123456789 by 2 and we get 246913578. Again
sum of individual digits of this number is also 45(=2+4+6+9+1+3+5+7+8) Also
note that no digit repeats in the result and no digit is missing between 1 and
9. What do you
observe when 123456789 is multiplied by 4,5,7,8?
3.
Let us look at the multiples of 9: They are 9, 18, 27, 36,
45, 54, 63, 72, 81, 90,99,108,117..( If we add the individual digits of these
multiples we get the sum as 9(1+8=9,2+7=9.. )
Properties of squares:
What did we notice?
The result of squaring a number can also
be arrived at by progressively adding consecutive odd numbers as shown above
Is this surprising? There is mathematics behind it if we
know the formula for formula for (a+b)2 which we learn later in algebra
Let us look at the expansion for (n+1)2 for any
number.
We learn later that (n+1)2= n2+2n+12=
n2+(2n+1).
Note here that here 2n+1 is a consecutive odd number after
the odd number in n2
Meru Prastara: Observe the following
arrangement of numbers:
In this triangle type of figure, at the tip is a small square containing the
number 1, which makes up the 0th row. In each row, value at the extreme
ends of the row on both sides are said to have value 0. The first row (1 &
1) contains two 1's, both formed by adding the two
numbers above them to the left and the right, in this case 1 and 0. Do the same
to create the 2nd row: 0+1=1; 1+1=2; 1+0=1. And the third:
0+1=1; 1+2=3; 2+1=3; 1+0=1. In this way, the rows
of the triangle go on forever. A number in the triangle can also be found by nCr (n Choose r) where n is the
number of the row and r is the order of element in the square corresponding to
that row. For example, in row 3, 1 is the 0th element, 3 is first
element, the next 3 is the 2nd element, and the last 1 is the 3rd
element. The formula for nCr
is: (We learn the concept in the chapter on
‘Permutations and Combinations’ later in a higher class)
First reference to this type of
arrangement was formed by Pingala(Period : 2nd BC). He used this concept in ‘Chandas Shastra’( Study of syllables). It was called ‘Meru Prastara’( Steps of Mountain – ‘Meru’ ). Halayudha
a 10th Century Mathematician provided commentary on this arrangement. As is the case with crediting all the
discoveries of Indian mathamaticians after
westerners, this triangle is now called Pascal triangle named after Pascal(17th Century) mach after its discovery and
relevance 1900 years ago!
Now lets us look at the some of
the properties of this Pingala’s Meru
Prastara.
Properties: Let n be the row number starting from 0
1.
Sum of the numbers across a horizontal row is always 2n
.( Ex 1 = 20 1+1=2=21,
1+2+1=4= 22 1+3+3+1=8=23,, Denoted by line marked as blue)
2.
The numbers when
arranged across a horizontal row
represents 11n ( Ex: 1= 110,11 = 111 ,121= 112,
1331= 113…Denoted by line marked as red
)
3.
The numbers across a diagonal represent natural numbers (1,2,3…. Denoted by squares in red
colour)
4.
The numbers across a diagonal when added with previous
numbers is a perfect square (1= 12, 1+3=4=22, 3+6=9=32,
6+10=16= 42,…. Denoted by squares in green colour)
(Perfect square is a number made by squaring a
whole number)
1.
If the 2nd element in a row is prime number other than 2, then all next numbers
in that row are multiples of it( 3, 3 in Row 3, 5,10,10,5 in Row5,
7,21,35,35,21,7 in Row 7)
Let us look at the above arrangement from a different
perspective
The numbers indicated in red are
the sum of numbers in diagonals. They are
1 1 2 3 5 8 13 21 34 55 89
Except for first number 1, each of the subsequent number
is sum of previous 2 numbers (13=5+8, 21=8+13, 34=13+21..)
Let us now look at another interesting mathematics concept
called Magic square
What do we observe in the figure? The figure has 3 rows (R1, R2 and R3). It
also has 3 columns (C1, C2 and C3) and in all has 9 squares (3*3). Squares are
filled with numbers from 1to 9 without any number repeating and without any
number missing from 1 to 9. We also observe
Sum of numbers in every Row (R1, R2 and R3) is 15
Sum of numbers in every column (C1, C2 and C3) is
15
Sum of numbers across 2 diagonals (joined by red
line) is also 15.
15 is called magic sum. ‘Magic sum’ is the sum of
all numbers in any row/column/diagonal in a magic square.
Observe the below mentioned figure
Above is another magic square whose magic sum is 30
and squares have all even numbers
without any repetition and without any missing number starting from 2 to 18.(In
all 9 even numbers)
Construction of magic square is very simple if you
can remember the right
angled triangle
For easy remembrance rule can be simply stated as
‘Diagonal, Down, Left’
Rules:
Start with placing the number in the top row and
middle column in an odd numbered square, and next number in the diagonal square
in the top
Rule
No |
Action |
1 |
If
there is no row and no column for a number then place the number immediately
below it else place
it in the bottom most square in the same column |
2 |
If
the square is already occupied, then place
it immediately below in the
same column |
3 |
If
there is no column then place the
number in extreme left square in the same row |
Let us see now how to use the above rules to
construct the Magic square given below
Step
No |
Action(Row
R0 and Column CL are only for demonstration) |
Movement
(Numbers in row R0 and Column CL have numbers which we place diagonally
before they are moved correctly in the magic square) |
1 |
Start
with number 1 in middle row, middle column(R1,C2) |
|
2 |
Try
to place next number 2 diagonally above, Since there is no row for that
number, but since there is column for that number, place it in the bottom
most square in the same column (R3,C3) – Rule 1 else Condition |
|
3 |
Try
to place next number 3 diagonally above, Since there is no column for that
number, place it in the extreme left square in the same row(R2,C1) –
Rule 3 |
|
4 |
Try
to place next number 4 diagonally above(R1,C2), Since that square is already
occupied , place it in the square below in the same column (R3,C1) –
Rule 2 |
|
5 |
Place
next 2 numbers diagonally. 5 in
(R2,C2), 6 in (R1,C3) |
|
6 |
Try
to place next number 7 diagonally above, Since there is no row and no column
for that number, place it just below 6. (R2,C3) – Rule 1 |
|
7 |
Try
to place next number 8 diagonally above, Since there is no column for that
number, place it in the extreme left square in the same row(R1,C1) –
Rule 3 |
|
8 |
Try
to place next number 9 diagonally above, Since there is no row for that
number, but since there is column for that number, place it in the bottom
most square in the same column (R3,C2) – Rule 1 else Condition |
|
Thus with just 3 easy rules and ‘Diagonal, Down, Left’ Concept
we are able to create a 3 by 3 Magic square
Similarly one can create 5 by 5 and 7 by 7 Magic
square an example of which is given below
In the above examples, 16 and 29 are marked in red to indicate
that only these 2 numbers do not follow the ‘else’
part in rule 1.
Now construct a 7 by 7 magic square with odd
numbers starting from 1 using the rules stated above as follows:
Construction of magic square with
magic sum of any given number
In the above figure note that sum of numbers in 4 rows(R,,R4),
sum of numbers in 4 columns(C1,,C4) and
sum of numbers in 2 diagonals(crossed by
red line) are all same and is equal to
45.
How do we construct such magic squares?
Let x be the given Magic sum for which we need to
construct the magic square. We use 9 in 4 different ways to fill the some of
the squares in a 4 by 4 square.
Step/Figure |
Action |
Movement |
1 |
Note 9= 5+4, use these 2 numbers
(5 and 4) to fill the squares in the squares
of last 2 rows(R3 and R4) in the
first column(C1) |
|
2 |
Note 9=1+8, use these 2 numbers(1 and 8) to fill the
squares in the squares of first
2 rows(R1 and R2) in the second
column(C2) |
|
3 |
Note 9= 3+6, use these 2 numbers
(3 and 6)to fill the squares in the squares
of last 2 rows(R3 and R4) in
the third column(C3) |
|
4 |
Note 9=7+2, use these 2 numbers(7and 2) to fill the
squares in the squares of first
2 rows(R1 and R2) in the fourth
column(C4) |
|
5 |
Place 9 in the
last row(R4) of last column(C4) |
|
6 |
Place 10, 11, 12 in the squares in (R3,C2),(R2,C1)
and (R1,C3) respectively as shown in the figure 6. |
|
7 |
If the magic sum required is X,
then place X-20,X-19,X-21,X-18 in
(R1,C1), (R4,C2),(R2,C3) and (R3,C4)
respectively as shown in the figure 7. |
|
.
Note the following in the figure/step number 7.
·
Sum of numbers in Row R1= X-20+1+12+7= X
·
Sum of numbers in Column C4 = 7+2+X-18+9=X
·
Sum of numbers in the diagonal top to bottom= X-20+8+3+9=X
·
Similarly one can observe that sum of numbers in other
rows, other columns and another diagonal is X
If we want a magic square whose magic sum required
is 45, then substitute 45 for x in the last figure to get the desired magic
square as in figure 8 which is what we started with as an example
Having seen and understood some of interesting
facts about numbers, let us learn about divisibility tips which are useful in
case of simplification:
Divisible by: |
If: |
Examples: |
2 |
The last digit is even (0,2,4,6,8) |
128
Yes 129
No |
3 |
The sum of the digits is divisible by
3 |
381 (3+8+1=12, and
12÷3 = 4) Yes 217 (2+1+7=10, and
10÷3 = 3 1/3) No |
4 |
The number formed by last 2 digits is divisible by 4 |
1312
Yes (12÷4=3) 7019
No |
5 |
The last digit is 0 or 5 |
175 Yes 809
No |
6 |
The number is divisible by both 2 and 3 |
114 (it is even, and
1+1+4=6 and 6÷3 = 2) Yes 308 (it is even, but
3+0+8=11 and 11÷3 = 3 2/3)
No |
7 |
If you double the last digit and
subtract it from the rest of the number and the answer is: ·
0, or ·
divisible by 7 (Note: you can apply this rule to
that answer again if you want) |
672 (Double of 2 is 4, 67-4=63, and 63÷7=9) Yes 905 (Double of 5 is 10, 90-10=80,
and 80÷7=11 3/7) No |
8 |
The number formed by last three
digits is divisible by 8 |
109816
(816÷8=102) Yes 216302
(302÷8=37 3/4) No |
9 |
The sum of the digits is divisible by
9 |
1629 (1+6+2+9=18, and again, 1+8=9) Yes 2013 (2+0+1+3=6) No |
10 |
The number ends in 0 |
220
Yes 221
No |
11 |
If
(sum of digits in even paces- sum of digits in odd places)= ·
0, or ·
divisible by 11 |
1364 ((3+4) - (1+6) = 0) Yes 3729 ((7+9) - (3+2) = 11) Yes 25176 ((5+7) - (2+1+6) = 3) No |
12 |
The number is divisible by both 3 and 4 |
648 524 |
1.1 Summary of learning
NO |
Points studied |
1 |
Meru Prastara Different types of majic squares |
2 |
Divisibility
test |